Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 245: 121

Answer

$-32a^5$

Work Step by Step

The given expression, $ (-2a)^5 $, simplifies to \begin{array}{l} (-2)^5a^5 \\\\= -32a^5 .\end{array}
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