Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set: 132

Answer

$13$

Work Step by Step

The given expression, $ (13^{-12})^2\cdot13^{25} $, simplifies to \begin{array}{l} 13^{-12(2)}\cdot13^{25} \\\\= 13^{-24}\cdot13^{25} \\\\= 13^{-24+25} \\\\= 13^{1} \\\\= 13 .\end{array}
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