Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 245: 114

Answer

$9.375\cdot 10^{2}$

Work Step by Step

$(1.5\cdot 10^{-3})\div(1.6\cdot 10^{-6})\qquad$...write as fraction. $=\displaystyle \frac{1.5\cdot 10^{-3}}{1.6\cdot 10^{-6}}\qquad$... write powers as a separate fraction. $=\displaystyle \frac{1.5}{1.6}\cdot\frac{10^{-3}}{10^{-6}}\qquad$...apply The Quotient Rule $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=\displaystyle \frac{1.5}{1.6}\cdot 10^{-3-(-6)}\qquad$...simplify. $=0.9375\cdot 10^{3}\qquad$...substitute $9.375\cdot 10^{-1}$ for $0.9375$ $=9.375\cdot 10^{-1}\cdot 10^{3}\qquad$...apply The Product Rule $a^{m}\cdot a^{n}=a^{m+n}$ $=9.375\cdot 10^{2}$
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