Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 106

Answer

$a^{8k}$

Work Step by Step

Using the laws of exponents, the given expression $ a^{10k}\div a^{2k} $ simplifies to \begin{array}{l}\require{cancel} a^{10k-2k} \\\\= a^{8k} .\end{array}
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