## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

If $t=2$, then the expression $\dfrac{t^6}{t^2}$ evaluates to \begin{array}{l}\require{cancel} \dfrac{2^6}{2^2} \\\\= \dfrac{64}{4} \\\\= 16 ,\end{array} and the expression $t^3$ evaluates to \begin{array}{l} 2^3 \\\\= 8 .\end{array} Hence, $\dfrac{t^6}{t^2} \ne t^3$.