Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 103

Answer

see explanation

Work Step by Step

If $t=2$, then the expression $ \dfrac{t^6}{t^2} $ evaluates to \begin{array}{l}\require{cancel} \dfrac{2^6}{2^2} \\\\= \dfrac{64}{4} \\\\= 16 ,\end{array} and the expression $ t^3 $ evaluates to \begin{array}{l} 2^3 \\\\= 8 .\end{array} Hence, $ \dfrac{t^6}{t^2} \ne t^3 $.
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