Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 237: 104

Answer

$\dfrac{a+7}{7}$

Work Step by Step

If $a=2$, then the expression $ \dfrac{a+7}{7} $ evaluates to \begin{array}{l}\require{cancel} \dfrac{2+7}{7} \\\\= \dfrac{9}{7} .\end{array} Hence, $ a \ne \dfrac{a+7}{7} $.
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