Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 102

Answer

see explanation

Work Step by Step

If $a=1$, then the expression $ (a+5)^2 $ evaluates to \begin{array}{l}\require{cancel} (1+5)^2 \\\\= (6)^2 \\\\= 36 ,\end{array} and the expression $ a^2+5^2 $ evaluates to \begin{array}{l} 1^2+5^2 \\\\= 1+25 \\\\= 26 .\end{array} Hence, $ (a+5)^2 \ne a^2+5^2 $.
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