Answer
$y=\frac{5}{3}x+5$
Work Step by Step
RECALL:
The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept.
The line in Exercise 16 has $(0, 5)$ as its y-intercept so $b=5$.
Thus, the tentative equation of the line is $ y=mx + 5$.
The line passes through the point $(-3, 0)$. To find the value of $m$, substitute the x and y coordinates of this point into the tentative equation above to obtain:
$y=mx+5
\\0=m(-3)+5
\\0=-3m+5
\\0-5=-3m
\\-5 = -3m
\\\frac{-5}{-3}=\frac{-3m}{-3}
\\\frac{5}{3} = m$
Therefore, the equation of the line in Exercise 16 is:
$y=\frac{5}{3}x+5$
