## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(\frac{C-D}{A}, 0)$
The x-intercept of the graph of a linear equation can be found by setting y=0 then solving for x. The given equation has no y-variable. Simply solve for x to obtain: $Ax+D=C \\Ax=C−D \\\dfrac{Ax}{A}=\dfrac{C−D}{A} \\x=\dfrac{C-D}{A}$ This means that the given equation is equivalent to $x=\dfrac{C-D}{A}$. RECALL: The x-intercept of the graph of $x=h$ is $(h, 0)$. Thus, the x-intercept of the given equation is: $(\frac{C-D}{A}, 0)$