Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 180: 103

Answer

$(\frac{C-D}{A}, 0)$

Work Step by Step

The x-intercept of the graph of a linear equation can be found by setting y=0 then solving for x. The given equation has no y-variable. Simply solve for x to obtain: $Ax+D=C \\Ax=C−D \\\dfrac{Ax}{A}=\dfrac{C−D}{A} \\x=\dfrac{C-D}{A}$ This means that the given equation is equivalent to $x=\dfrac{C-D}{A}$. RECALL: The x-intercept of the graph of $x=h$ is $(h, 0)$. Thus, the x-intercept of the given equation is: $(\frac{C-D}{A}, 0)$
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