Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 180: 98



Work Step by Step

RECALL: The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. The graph in Exercise 98 has $(0, 5)$ as its y-intercept so $b=5$. Thus, the tentative equation of the line is $ y=mx + 5$. The line passes through the point $(2, 0)$. To find the value of $m$, substitute the x and y coordinates of this point into the tentative equation above to obtain: $y=mx+5 \\0=m(2)+5 \\0=2m+5 \\0-5=2m \\-5 = 2m \\\frac{-5}{2}=\frac{2m}{2} \\-2.5 = m$ Therefore, the equation of the line in Exercise 98 is: $y=-2.5x+5$
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