Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 180: 101



Work Step by Step

The y-intercept of a linear equation can be found by setting $x=0$ then solving for $y$. Set $x=0$ then solve for $y$ to obtain: $4x=C-3y \\4(0)=C-3y \\0=C-3y \\3y=C \\\frac{3y}{3}=\frac{C}{3} \\y =\frac{C}{3}$ The y-intercept is given to be $(0, -8)$. This means that: $\frac{C}{3}=-8$ Solve the equation to obtain: $\frac{C}{3}=-8 \\3 \cdot (\frac{C}{3})=3(-8) \\C=-24$
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