## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$s=2A-p-230$
Using the properties of equality, in terms of $s$, the given equation, $A=115+\dfrac{1}{2}(p+s)$, is equivalent to \begin{array}{l} 2(A)=2(115)+1(p+s) \\\\ 2A=230+p+s \\\\ 2A-230-p=s \\\\ s=2A-p-230 .\end{array}