Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set: 30

Answer

$q=r-2p$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ p=\dfrac{r-q}{2} $ for $ q ,$ use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} p=\dfrac{r-q}{2} \\\\ 2\cdot p=2\cdot \dfrac{r-q}{2} \\\\ 2p=r-q \\\\ q=r-2p .\end{array}
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