#### Answer

$C=\dfrac{5}{9}(F-32)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To solve the given equation, $
F=\dfrac{9}{5}C+32
$ for $
C
,$ use the properties of equality to isolate the variable.
$\bf{\text{Solution Details:}}$
Using the properties of equality to isolate the variable, the equation above is equivalent to
\begin{array}{l}\require{cancel}
F=\dfrac{9}{5}C+32
\\\\
F-32=\dfrac{9}{5}C
\\\\
5(F-32)=5\left( \dfrac{9}{5}C \right)
\\\\
5(F-32)=9C
\\\\
\dfrac{5(F-32)}{9}=\dfrac{9C}{9}
\\\\
\dfrac{5}{9}(F-32)=C
\\\\
C=\dfrac{5}{9}(F-32)
.\end{array}