Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set - Page 101: 33



Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ H=\dfrac{TV}{550} $ for $ T ,$ use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} H=\dfrac{TV}{550} \\\\ 550\cdot H=550\cdot\dfrac{TV}{550} \\\\ 550H=TV \\\\ \dfrac{550H}{V}=\dfrac{TV}{V} \\\\ \dfrac{550H}{V}=T \\\\ T=\dfrac{550H}{V} .\end{array}
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