Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 48

Answer

$a_n=\frac{1}{2^n}$

Work Step by Step

If we look at the pattern: $ \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, ...$ $\frac{1}{2^1}, \frac{1}{2^2}, \frac{1}{2^3}, \frac{1}{2^4}, ...$ The nth term in the sequence is: $a_n=\frac{1}{2^n}$
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