Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 18

Answer

-37916508.16

Work Step by Step

If we want to find the 23rd term, we have to substitute $n$ by 23: $a_{23}=(-2)^{23-2}(45.68-1.2(23))=(-2)^{21}(45.68-27.6)=-2097152(18.08)=-37916508.16$
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