Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 19

Answer

-363

Work Step by Step

If we want to find the 11th term, we have to substitute $n$ by 11: $a_{11}=3(11)^2(9(11)-100)=3\times121\times(99-100)=363\times(-1)=-363$
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