Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 23

Answer

$a_{1}=3(1)-1=2$ $a_{2}=3(2)-1=5$ $a_{3}=3(3)-1=8$ $a_{4}=3(4)-1=11$ $a_{10}=3(10)-1=29$ $a_{15}=3(15)-1=44$

Work Step by Step

If we want to find a term, we have to substitute $n$ by its index: $a_{1}=3(1)-1=2$ $a_{2}=3(2)-1=5$ $a_{3}=3(3)-1=8$ $a_{4}=3(4)-1=11$ $a_{10}=3(10)-1=29$ $a_{15}=3(15)-1=44$
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