## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(x-5)^2+(y-6)^2=11$
Using $(x-h)^2+(y-k)^2=r^2$ or the Center-Radius form of the equation of circles, the equation of the circle with center $( 5,6 )$ and radius, $r= \sqrt{11} ,$ is \begin{array}{l}\require{cancel} (x-5)^2+(y-6)^2=\left( \sqrt{11} \right)^2 \\\\ (x-5)^2+(y-6)^2=11 .\end{array}