## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

The graph for equation $x={{y}^{2}}-1$.
$x={{y}^{2}}-1$ (equation -1) \begin{align} & y=-\frac{b}{2a} \\ & =-\frac{\left( 0 \right)}{2\cdot \left( 1 \right)} \\ & =0 \end{align} Now for the x value put $y=0$ in equation (1). \begin{align} & x={{\left( 0 \right)}^{2}}-1 \\ & =-1 \end{align} The vertex is$\left( -1,0 \right)$. Now choose some value of x on both sides of the vertex and compute the corresponding y value $\begin{matrix} x & y \\ 0 & 1 \\ 3 & 2 \\ 0 & -1 \\ -2 & 3 \\ -1 & 0 \\ \end{matrix}$