Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - 13.1 Conic Sections: Parabolas and Circles - 13.1 Exercise Set - Page 854: 13

Answer

The equation $y=-{{x}^{2}}$.

Work Step by Step

The equation is equivalent to $y=-{{\left( x-0 \right)}^{2}}+0$. Now choose some value of x on both sides of the vertex and compute the corresponding y value. $\begin{matrix} x & y \\ 0 & 0 \\ 1 & -1 \\ 2 & -4 \\ -1 &-1 \\ -2 & -4 \\ \end{matrix}$ Now plot all the values of x and y on the rectangular coordinate system and join each point with one another to form a parabola. It can be concluded that the graph opens down because the coefficient of ${{x}^{2}}$ is negative
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