## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

The graph for the equation $y=-\frac{1}{2}{{x}^{2}}$.
$y=-\frac{1}{2}{{x}^{2}}$ (equation - 1) \begin{align} & x=-\frac{b}{2a} \\ & =-\frac{\left( 0 \right)}{2\cdot \left( -\frac{1}{2} \right)} \\ & =0 \end{align} Now for the y value put $x=0$ in equation (1), \begin{align} & y=-\frac{1}{2}{{\left( 0 \right)}^{2}} \\ & =0 \end{align} The vertex is $\left( 0,0 \right)$. Now choose some value of x on both sides of the vertex and compute the corresponding y value. $\begin{matrix} x & y \\ 0 & 0 \\ -2 & -2 \\ 4 & -8 \\ 2 & -2 \\ -4 & -8 \\ \end{matrix}$