Answer
True statement
Work Step by Step
$a{{x}^{2}}+bx+c=0$
Any other trinomial of the form $d{{x}^{m}}+e{{x}^{n}}+f=0$ (where m and n are integers and $n\ne 0$) can be reduced to quadratic form if $m=2n$ by substituting ${{x}^{n}}=u$.
$\begin{align}
& d{{x}^{m}}+e{{x}^{n}}+f=0 \\
& d{{\left( {{x}^{n}} \right)}^{2}}+e\left( {{x}^{n}} \right)+f=0 \\
& d{{u}^{2}}+eu+f=0
\end{align}$
$d{{u}^{2}}+eu+f=0$ is the reduced quadratic form of $d{{x}^{m}}+e{{x}^{n}}+f=0$.
Thus, the given statement is true.
