Answer
Fill the blank with $\sqrt{p}$.
Work Step by Step
With substitution $u=\sqrt{p},\ p=u^{2}$, the equation becomes
$3u^{2}-4u+6=0$.
Thus, we are able to substitute $\sqrt{p}$ for $u$.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 11 - Quadratic Functions and Equations - 11.5 Equations Reducible to Quadratic - 11.5 Exercise Set - Page 731: 5
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