Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 726: 67

Answer

$A=\pi \frac{S}{6}$

Work Step by Step

Let $s$ represent a length of a side of the cube and $S$ represent the surface area of the cube. Let $A$ represent the surface area of the sphere. Surface area of the sphere is, $A=4\pi {{r}^{2}}$ Substitute the value $r=\frac{s}{2}$ in the equation. $\begin{align} & A=4\pi {{r}^{2}} \\ & =4\pi {{\left( \frac{s}{2} \right)}^{2}} \\ & =4\pi \frac{{{s}^{2}}}{4} \\ & =\pi {{s}^{2}} \end{align}$ Therefore, the surface area of the sphere is $\pi {{s}^{2}}$. The surface area of the cube is $S=6{{s}^{2}}$. Divide both the sides of the equation $S=6{{s}^{2}}$ by 6, $\begin{align} & \frac{S}{6}=\frac{6{{s}^{2}}}{6} \\ & \frac{S}{6}={{s}^{2}} \end{align}$ $\begin{align} & A=\pi {{s}^{2}} \\ & =\pi \frac{S}{6} \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.