Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.1 Quadratic Equations - 11.1 Exercise Set - Page 707: 92

Answer

324 ft

Work Step by Step

$s=16{{t}^{2}}$ For the height $\left( s \right)$, The object falls for 4.5 seconds. For $\left( s \right)$, put $\left( t=4.5\text{sec} \right)$ in the expression, $\begin{align} & s=16{{t}^{2}} \\ & =16\times {{\left( 4.5 \right)}^{2}} \\ & =16\times 4.5\times 4.5 \\ & =324 \end{align}$ Therefore, it is $324\text{ft}$ above the ground.
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