Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.1 Quadratic Equations - 11.1 Exercise Set - Page 707: 77

Answer

$ 4\%$

Work Step by Step

$ A=P(1+r)^{t}\qquad$..Substitute $6760$ for $A,\ 6250$ for $P$ and $2$ for $t$. $ 6760=6250(1+r)^{2}\qquad$..divide both sides by $6250$. $\displaystyle \frac{6760}{6250}=(1+r)^{2}\qquad$..simplify. $\displaystyle \frac{676}{625}=(1+r)^{2}$ According to the general principle of square roots: For any real number $k$ and any algebraic expression $x$ : $\text{If }x^{2}=k,\text{ then }x=\sqrt{k}\text{ or }x=-\sqrt{k}$. $ 1+r=\pm\sqrt{\frac{676}{625}}\qquad$..add $-1$ to both sides. $ 1-1+r=\displaystyle \pm\frac{\sqrt{676}}{\sqrt{625}}-1\qquad$..simplify. $ r=-\displaystyle \frac{25}{25}\pm\frac{26}{25}\qquad$.. The interest rate cannot be negative, we eliminate the negative solution. $ r=-\displaystyle \frac{25}{25}+\frac{26}{25}=0.04=4\%$
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