Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.1 Quadratic Equations - 11.1 Exercise Set - Page 707: 67

Answer

$$x=2,\:x=-\frac{1}{3}$$

Work Step by Step

In order to solve this problem, we use the method of completing the square. Doing this, we find: $$ x^2-\frac{5x}{3}=\frac{2}{3} \\ x^2-\frac{5x}{3}+\left(-\frac{5}{6}\right)^2=\frac{2}{3}+\left(-\frac{5}{6}\right)^2\\ \left(x-\frac{5}{6}\right)^2=\frac{49}{36}\\ x=2,\:x=-\frac{1}{3}$$
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