Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 654: 83



Work Step by Step

Consider the following example: $$ \frac{\sqrt{48}}{\sqrt{3}}\\ \frac{2^2\sqrt{3}}{\sqrt{3}}\\ 4$$ Here, we see that we started with two irrational numbers, one in the numerator and one in the denominator, but the result is not an irrational number.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.