Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set: 66

Answer

$\dfrac{6}{\sqrt{15y}}$

Work Step by Step

Rationalizing the numerator, the given expression, $ \dfrac{\sqrt{12}}{\sqrt{5y}} ,$ is equivalent to \begin{array}{l} \dfrac{\sqrt{12}}{\sqrt{5y}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}} \\\\= \dfrac{\sqrt{36}}{\sqrt{15y}} \\\\= \dfrac{6}{\sqrt{15y}} .\end{array}
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