Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 654: 63



Work Step by Step

Rationalizing the numerator, the given expression, $ \dfrac{2\sqrt{6}}{5\sqrt{7}} ,$ is equivalent to \begin{array}{l} \dfrac{2\sqrt{6}}{5\sqrt{7}}\cdot\dfrac{\sqrt{6}}{\sqrt{6}} \\\\= \dfrac{2\sqrt{6^2}}{5\sqrt{42}} \\\\= \dfrac{2(6)}{5\sqrt{42}} \\\\= \dfrac{12}{5\sqrt{42}} .\end{array}
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