Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set: 99

Answer

all real numbers

Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given function, $ f(t)=\sqrt[5]{2t+7} ,$ is the permissible values of $x.$ $\bf{\text{Solution Details:}}$ With an odd index (index equals $ 5 $), then the radicand can be any real number. Hence, the domain is the set of $\text{ all real numbers .}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.