## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\bf{\text{Solution Outline:}}$ The domain of the given function, $f(t)=\sqrt[5]{2t+7} ,$ is the permissible values of $x.$ $\bf{\text{Solution Details:}}$ With an odd index (index equals $5$), then the radicand can be any real number. Hence, the domain is the set of $\text{ all real numbers .}$