Answer
Domain: $[2,\infty)$
Work Step by Step
$\bf{\text{Solution Outline:}}$
The domain of the given function, $
f(x)=\sqrt{x-2}
,$ are the permissible values of $x.$ Then use a table of values to graph the function.
$\bf{\text{Solution Details:}}$
Since the radicand of a radical with an even index (index equals $2$), should be nonnegative, then
\begin{array}{l}\require{cancel}
x-2\ge0
\\\\
x\ge2
.\end{array}
Hence, the domain is the interval $
[2,\infty)
.$
Use the table of values below to get the graph of the function.