#### Answer

$(-\infty,0)\cup(0,\infty)$

#### Work Step by Step

The denominator of the function, $g(x)=\dfrac{1}{x},$ cannot be zero. Hence, the domain is the interval $
(-\infty,0)\cup(0,\infty)
.$

Published by
Pearson

ISBN 10:
0-32184-874-8

ISBN 13:
978-0-32184-874-1

$(-\infty,0)\cup(0,\infty)$

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