Answer
$(fg)(x)=\dfrac{3x-1}{x}$
Work Step by Step
Since $(fg)(x)=f(x)g(x),$ with $f(x)=3x-1$ and $g(x)=\dfrac{1}{x},$ then
\begin{array}{l}\require{cancel}
(fg)(x)=f(x)g(x)
\\\\
(fg)(x)=(3x-1)\left(\dfrac{1}{x}\right)
\\\\
(fg)(x)=\dfrac{3x-1}{x}
.\end{array}