Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-9 - Cumulative Review - Page 625: 32

Answer

$$[-4,0), (0,\infty)$$

Work Step by Step

We see that the denominator cannot be zero, so $x$ cannot be zero. We see that the value inside of the square root must be positive, so $x$ must be greater than or equal to $-4$. Thus, we find: $$[-4,0), (0,\infty)$$
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