Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-9 - Cumulative Review - Page 625: 14



Work Step by Step

Solving the problem by cross multiplying, we obtain: $$ 3\cdot \:4=\left(x+1\right)x\\ 12=\left(x+1\right)x\\ x=3,\:x=-4$$
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