Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-9 - Cumulative Review - Page 625: 24

Answer

22

Work Step by Step

Plugging in $-2$ for $x$, we find: $$ 3\left(-2\right)^2-5\left(-2\right)\\ 3\cdot \:4-5\left(-2\right)\\ 12-\left(-10\right)\\22$$
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