Answer
$$x=4,\:x=-2$$
Work Step by Step
Solving the problem by using the quadratic formula, we obtain:
$$ x^2-2x-8=0\\ x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}\\ x=4,\:x=-2$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1-9 - Cumulative Review - Page 625: 13
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