Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Divide both sides by $5$: $\require{cancel} \dfrac{5(7+x)}{5}=\dfrac{(x+6)5}{5} \\\dfrac{\cancel{5}(7+x)}{\cancel{5}}=\dfrac{(x+6)\cancel{5}}{\cancel{5}} \\7+x=x+6$ Subtract $x$ to both sides: $7+x-x=x+6-x \\7=6$ The statement above is false; therefore the equation has no solution.