Answer
The equation has no solution.
Work Step by Step
Divide both sides by $5$:
$\require{cancel}
\dfrac{5(7+x)}{5}=\dfrac{(x+6)5}{5}
\\\dfrac{\cancel{5}(7+x)}{\cancel{5}}=\dfrac{(x+6)\cancel{5}}{\cancel{5}}
\\7+x=x+6$
Subtract $x$ to both sides:
$7+x-x=x+6-x
\\7=6$
The statement above is false; therefore the equation has no solution.
