Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-3 - Cumulative Review - Page 228: 39


The equation has no solution.

Work Step by Step

Divide both sides by $5$: $\require{cancel} \dfrac{5(7+x)}{5}=\dfrac{(x+6)5}{5} \\\dfrac{\cancel{5}(7+x)}{\cancel{5}}=\dfrac{(x+6)\cancel{5}}{\cancel{5}} \\7+x=x+6$ Subtract $x$ to both sides: $7+x-x=x+6-x \\7=6$ The statement above is false; therefore the equation has no solution.
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