Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\color{blue}{y-4=-\frac{3}{8}(x+6)}$
RECALL The point-slope-intercept form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. The given equation has a slope of $-\frac{3}{8}$ and contains the point $(-6, 4)$. Thus, the equation of the given line in point-slope form is: $y-4=-\frac{3}{8}[x-(-6)] \\\color{blue}{y-4=-\frac{3}{8}(x+6)}$