Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-3 - Cumulative Review: 10

Answer

$-\frac{5}{12}$

Work Step by Step

Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}$ to obtain: $=\frac{3}{8} \times \left(-\frac{10}{9}\right)$ The product of the two numbers is negative. Cancel common factors then multiply to obtain: $\require{cancel} =\frac{\cancel{3}}{\cancel{8}4} \times \left(-\frac{\cancel{10}5}{\cancel{9}3}\right) \\=\frac{1}{4} \times (-\frac{5}{3}) \\=-\frac{5}{12}$
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