Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-3 - Cumulative Review: 20

Answer

$h=\frac{A-\pi{r^2}}{2\pi{r}}$

Work Step by Step

Subtract $\pi{r^2}$ to both sides: $A-\pi{r^2}=2\pi{rh}+\pi{r^2}-\pi{r^2} \\A-\pi{r^2}=2\pi{rh}$ Divide $2\pi{r}$ to both sides: $\frac{A-\pi{r^2}}{2\pi{r}}=\frac{2\pi{rh}}{2\pi{r}} \\\frac{A-\pi{r^2}}{2\pi{r}}=h$
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