## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 1-2 - Cumulative Review: 8

#### Answer

$-21n+36$

#### Work Step by Step

Removing the grouping symbol and then combining like terms, the given expression, $3[4n-5(2n-1)]-3(n-7)$, simplifies to \begin{array}{l}\require{cancel} 3[4n-10n+5]-3n+21 \\\\= 3[-6n+5]-3n+21 \\\\= -18n+15-3n+21 \\\\= (-18n-3n)+(15+21) \\\\= -21n+36 .\end{array}

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