Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-2 - Cumulative Review - Page 152: 12



Work Step by Step

Using the properties of equality, the solution to the given equation, $ \dfrac{2}{3}t+7=13 $, is \begin{array}{l}\require{cancel} \dfrac{2}{3}t=13-7 \\\\ \dfrac{2}{3}t=6 \\\\ 2t=3(6) \\\\ t=\dfrac{3(6)}{2} \\\\ t=\dfrac{3(\cancel{2}\cdot3)}{\cancel{2}} \\\\ t=9 .\end{array}
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