Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-2 - Cumulative Review - Page 152: 6



Work Step by Step

Using order of operations, the given expression, $ (150-10^2)\div(25\cdot4) $, simplifies to \begin{array}{l}\require{cancel} (150-100)\div(100) \\\\= 50\div100 \\\\= \dfrac{50}{100} \\\\= \dfrac{1}{2} .\end{array}
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