Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-2 - Cumulative Review - Page 152: 13



Work Step by Step

Using the properties of equality, the solution to the given equation, $ 9(2a-1)=4 $, is \begin{array}{l}\require{cancel} 9(2a)+9(-1)=4 \\\\ 18a-9=4 \\\\ 18a=4+9 \\\\ 18a=13 \\\\ a=\dfrac{13}{18} .\end{array}
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