Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5 - Page 425: 53

{$110$}

Step 1: $\sqrt[3] {2x-4}=6$ Step 2: Raising each side of the equation to the power of $3$ and simplifying, we obtain: $(\sqrt[3] {2x-4})^{3}=(6)^{3}$ $2x-4=216$ Step 3: Solving the equation, we obtain: $2x-4=216$ $2x=216+4$ $2x=220$ $x=\frac{220}{2}$ $x=110$ Therefore, the solution set of the equation is {$110$}.