Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5: 52

Answer

{$4$}

Work Step by Step

Step 1: $\sqrt[3] {x-12}=-2$ Step 2: Raising each side of the equation to the power of $3$ and simplifying, we obtain: $(\sqrt[3] {x-12})^{3}=(-2)^{3}$ $x-12=-8$ Step 3: Solving the equation, we obtain: $x-12=-8$ $x=-8+12$ $x=4$ Therefore, the solution set of the equation is {$4$}.
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